Metamfetamino sintezė iš P2P redukuojant NaBH4. Vidutinės apimties.

btcboss2022

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Sveiki,

Po daugybės bandymų, atliktų naudojant metilamino HCL pagal šį metodą, pasidalysiu geriausiu būdu, kurį radau, kaip gauti metamfetamino laisvąją bazę dideliu mastu:

  • 966 gr P2P
  • 14 litrų metanolio
  • 1183 gr Metilamino HCL
  • 638 gr NaOH
  • 452 gr Bevandenis natrio sulfatas
  • 105 gr NaBH4
  • 35 l distiliuoto vandens
  • 7 litrai DCM

- Pripildykite reaktorių 14 l metanolio
- Maišant ištirpinkite metilamino HCL
- Nustatykite reaktoriaus temperatūrą 0C (ne mišinio temperatūrą) ir įpilkite NaOH, temperatūra padidės
- Kai temperatūra vėl pasieks 20C, įpilkite P2P, temperatūra padidės, maišykite 45 min. iki 1 val.
- Įpilkite 252 g bevandenio natrio sulfato
- Kai mišinio temperatūra pasiekia 8C, pradėkite dalimis pilti NaBH4, neviršydami 20C temperatūros
- Kai bus įdėtas visas NaBH4, leiskite mišiniui maišytis 20C temperatūroje maždaug 2 valandas, kol nustos burbuliuoti
- Įpilkite vandens ir maišykite 5 min.
- Įpilkite DCM ir maišykite 10 min.
- Nustokite maišyti ir leiskite sluoksniams atsiskirti
- Pasilikite apatinį sluoksnį, o viršutinį išmeskite (nėra naudinga ekstrahuoti šią vandeninę fazę)
- Į išsaugotą sluoksnį įpilkite 200 g bevandenio natrio sulfato ir išmaišykite
- Filtruokite Buchnerio piltuvu
- Išgarinkite DCM
- Gaunama švari ir kvapni metamfetamino laisvoji bazė

;-)
 
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snowbones

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Is the 35 litres of water added to ensure seperation of the dcm and water cos of the methanol present to stop it all mixing?
and are you using a 100 litre HDPE paint bucket as the reaction vessel?
 

Chemistry lntern

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Excuse me! Is it necessary to use an ice bath when setting the reaction temperature to 0 degrees (not the temperature of the mixture
 

Atompower

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Has any one trying this method of btc boss and had success with his write up
 

rage565

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Is there a video of this procedure available?
 

G.Patton

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Have you tried to open Video section?
 

Grubby

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Is 15g of NaBH4 enough as the reducing agent for 138g of P2P? Or should I add a small amount of reducing agent to avoid some side reactions?
 

G.Patton

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Hello, yes it's not enough. You have to add at least equimolar amount 38.91g of NaBH4. It's even worth to add a little more, ~1.1 eqviv 42.8g.
 

Grubby

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Idol, there must be a special reason why you choose to use less reducing agent! For example, to avoid certain side reactions or to favor certain steps? Please Master, please enlighten me on the mystery behind this.
 

GnarleyBarley

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You don't need that much, 15 g (maybe a tiny bit more) is enough. 1 mol NaBH4 can reduce more than just 1 mol of imine. It can theoretically reduce 4 moles!!!

Don't know why patton says otherwise, but it's not true. and countless of articles, synthesis on forums and so on pretty much proves it

The following is for MDMA but the same molar ratio of NaBH4 applies to methamphetamine synthesis (here 0.47 equivalents is used)
0xX6LgyRST
 

Chemistry lntern

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How does methylamine hydrochloride and methanol produce a 10% methylamine methanol solution
 

GnarleyBarley

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Methylamine hydrochloride in methanol, add naoh.
You now need to filter the solution (NaCl is precipitated) and dry it with something (sieves, mgso4 etc). Filter it again
or just filter it one time after mgso4

Notice: More products are formed than what is shown in the table below (NaCl) is not shown because I don't care about how many grams of NaCl is produced, it will be filtered of anyway

CH6ClN = Methylamine hydrochloride, CH5N = methylamine, HNaO is NaOH (This table was made automatically in chemdraw, and this is how they do it.
KbwCJYLjef


As you can see, 26g of water is produced to make 45g methylamine from 98g of methylamine hydrochloride. Therefor you need something to dry up all the 26g of water (minimum)

I failed this reaction when I didn't dry it enough (because I didn't realize that so much water was actually produced (just added a little bit of mgso4 and thought I was good to go)

Also you don't need to have exactly 10% Methanol solution. Just enough to hold all the methylamine and enough to keep dilute the reaction enough.
 

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