kena ja tõhus marsruut ise 2b4m süntehsis (avg 50 usd kg)

[Dr. MMX]

Hei ma lihtsalt kirjutan kasutatud reaktiivid targa valiku (hind/kulu) aviable to buy in europe
nii 1.
PCL5 koos elementaarse väävliga > tionüülkloriidiga

tionüülkloriid + propioonhape > priopionüülkloriid

4mp süntees (siin on teemato ill lihtsalt link):
Propionüülkloriid
Tolueen
AlCl3 veevaba

http://bbzzzsvqcrqtki6umym6itiixfhni37ybtt7mkbjyxn2pgllzxf2qgyd.onion/en/threads/synthesis-of-4-methylpropiophenone-from-toluene-by-friedel-crafts-reaction-1kg-scale.209/

mõnedel on probleemiks broomineerida seda
väävelhape, mis on vajalik Hbr saamiseks, mis on natuke kallis ja mitte sageli kättesaadav. Selle asemel kasutame:
Fosforhapet ja NaBh reaktsiooniks > saame HBR.
H2O2 12% saab osta ja destilleerida veel mõnele protsendile, näiteks 25-30%.

nii et
4 metüülpropioon + HBR + h2o2 > 2b4m

Ma ei ole arvutanud kulusid, kuid need on väga väikesed ja ei pea ootama saadetist või olema üllatunud madala kvaliteediga lähteaine üle.

 

[chost]

kas te oskate täpsemalt selgitada, kuidas HBRi valmistada?

 

[Dr. MMX]

Oh am tõesti sorry, et tegin vea. selle õige:
Fosforhappest (H₃PO₄) ja naatriumbromiidist (NaBr) vesinikbroomhappe (HBr) tootmiseks saab kasutada kahekordset nihutusreaktsiooni. Reaktsiooni võib esitada järgmiselt:

1. Reaktandid: Fosforhape (H₃PO₄) ja naatriumbromiid (NaBr).
2. Tooted: Bromvesinikhape (HBr) ja naatriumfosfaat (Na₃PO₄).

Reaktsiooni tasakaalustatud keemiline võrrand on:


H3PO4+3NaBr→3HBr+Na3PO4


Selles reaktsioonis reageerib fosforhape naatriumbromiidiga, mille tulemuseks on bromvesinikhape ja naatriumfosfaat.

 

[chost]

Kas destilleerimine on vajalik?
Ja kui suures koguses vees peaksin ma naatriumbromiidi lahustama?

 

[Dr. MMX]

Kuidas muidu kavatsete saada asja, mis on põhimõtteliselt gaas?

See sõltub sellest, millist % sa tahad, max on minu mäletamist mööda 47% ja see peaks olema juba nii

 

[Benz88]

is it Safe to Distille the h2o2 to maybe 30-35% from 12%?

 

[TheVacuumGuy]

H3po4 koos NaBriga, et toota HBr? Lähen kohe proovima.

On palju HBr, kuid lihtsalt uudishimulik, kas 2 reageerivad.

 

[Dr. MMX]

jah ja Na3PO4

 

[Dr. MMX]

See on imeline

 

[TheVacuumGuy]

Didn't work. I think it would be easier to add sulfuric acid to a solution of KBr (or NaBr) , which would readily yield HBr at 125c

 

[Dr. MMX]

I tried to override having sulfuric acid becasue here is troubles to get it. It was very extreme attempt
if there is access to sulfuric acid its easy job

 

[Dr. MMX]

you can get elemental bromine from potasium bromide, dont need to use acids.
it was quite cheap as i remember

 

[Toddler]

Hbr2 48% can work ?
(CAS.No: 10035-10-6)

how much ration use for bromination
Hbr2
H2O2
for 100g of 4MPP

 

[TheVacuumGuy]

Roughly,

H2o2 50ml
HBr 100ml

 

[Toddler]

for 100g of 4MPP

 

[w2x3f5]

Instead of propionyl chloride, can use propionic anhydride (obtain phosphorus oxide from propionic acid), can also use propionic acid directly with polyphosphoric acid (there are many options for this reaction, you can choose the best one). If propionyl chloride is used with anhydrous aluminum chloride (can be replaced with cheaper and simpler options). Then it is best to carry out a bromination reaction before hydrolysis in Fridel-Crafts (the complex of 2b4m and aluminum chloride is very active for bromination with a high yield).

 

[Dr. MMX]

In chemistry trade buissness in europe propionic acid is considered with "silent restriction" with reason it can be used as biological weapon, so should be avoided there.

very interesting choice of propionic anhydride

 

[Osmosis Vanderwaal]

@TheVacuumGuy you gave him bad figures and he used them and probably ruined 100G 2B4-MP. I dont know what he paid, but I got $200 all day for 10g if it's domestic . In th rules there are a few gold nuggets. "Use the fucking search engine." That's a rule. Another one is " a good chemist i an accurate chemist." Make sure that you clearly state you are guessing when you don't know. You could say nothing at all, you could show your math or you could tell him he needs to figure it himself, but please, dont just throw out random numbers, with no disclaimer.