Is my synthesis procedure of Mephedron right?

Brambus

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Hello everybody, i have been working on the following procedure hoping a good chemist will read it and give me a note when it is incorrect thank you!

Synthesis procedure

1. 2-Bromo-4'-methylpropiophenone 100g is poured into the reaction vessel.

2. DMF 400mL is poured into the flask. Top stirrer is turned on and the reaction mixture is heated up to 40 °С.

3. When temperature is reached 40 °С, methylamine HCL 80 mL is poured into the reaction mixture and stirred for 20 min.

4. 20 min have passed. Next, distilled cold water 1 L (Room temperature) is poured into reaction mixture and stirred for few minutes.

5. Ethyl acetate (EA) 500ml is poured into the cylinder. Stir for 1 a 2 minutes.

6. Than, the stirrer is stopped, the mixture is divided into two layers.

7. The upper base extract with EA is poured into a beaker.

8. Anhydrous acetone 500 mL is added to the reaction mixture and hydrochloric acid (HCl 48%) is added dropwise (in the drip funnel) (for further crystallization) with a constant stirring to reach pH 4-5.

9. Let the mixture precipitate.

10. Then the mixture is put in a freezer for at least 24h for better crystallization.

11. Mephedrone is filtered using vacuum.

12. Product is rinsed with cold acetone until white.

13. After drying, IPA(isopropyl alcohol)+ water solution (30:70) is poured.

14. The product is left for a few days for recrystallization.
 

Osmosis Vanderwaal

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I just checked the pH of 2-b-4-mp. 5.5 I don't think that is going to deprotonate the HCL on the methylammonium chloride. I'm not a chemist but doesn't this rxn with CH³NH²HCL require NaOH or another strong base to liberate the methylamine? 48% HCL seems awfully hot to use directly , it's 13mol I calculated (/L). Methylamine HCL is a solid, so 80ml is awfully ambiguous. 80ml of what mol. Strength? I haven't looked up the solvency but I know that methylamine gas can only reach 50% w/w in water
 
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Brambus

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Thank you for your reply, good points and also good to know that methylamine gas can only reach 50% w/w in water i was just working on something related!
 

Berlin777

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how have you acquired HCl 48%?
 

Brambus

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A supplier of mine in poland can get it, but i will go with the recommendations and go for a lower percentage anyway.
 

PersonVPN

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1) Bro !) Methylamine hydrochloride and 40% aqueous solution of methylamine are completely different substances! :)
Therefore, according to your scheme, nothing will work out for you!
This site has a detailed video on how to do it right
2) I have never seen hydrochloric acid 48% before :) :) :)
48% There is hydrobromic acid, But she's expensive. 37% is enough for you.
3) Study the video carefully. It will help you avoid many mistakes.
4) DMF very, very, toxic and has a strong effect on the heart! Better take it DMSO ! In addition, it is available for free sale

I hope I helped you at least a little! :) :) :)
 

spongebomb

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@PersonVPN
at point 4) the quantities remain the same with DMSO (as with NMP, for example) ?
 

PersonVPN

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There will be no difference in the reaction, even if you take 200-300 or 400 ml (DMSO; NMP )
Simply due to the smaller volume, the RM will heat up more! And you will have to cool more intensively.
I strongly do not recommend pouring the entire solution of aqueous methylamine into the mixture of solvent and ketone at once!
At the beginning, add no more than 20% methylamine to RM.
Otherwise, you will get a sad experience and a cleanup of the workplace.:) :) :)
WARNING !!!
ATTENTION !

Do not conduct experiments with bromination or BK4 in a residential area!!!
Otherwise, lachrimators will remind you of themselves for a long time :) :) :) :)
 

Berlin777

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3. it should be either 200mL MA 40% or 150g MA HCl
 

PersonVPN

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I think that TS simply does not understand the difference between a 40% aqueous solution of MA, and MA HCL (hydrochloride)
Perhaps the following link will help him understand the difference:
 
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Berlin777

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Or he could just simply follow my method which is posted on the forum instead of complicating
 

Brambus

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@Berlin777 I am very interested in your method but i couldnt find your method, could you share the link for me??
 

Berlin777

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Brambus

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Thank you, that sounds straight forward and practical! I think the quantities you used of NAOH and water are for 1kg of 2B4M? And you do this process during the synthesis in the reaction vessel, if i understand correctly?
 

Berlin777

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Here are the proportions I use:
BK4 - NaOH 1:1
BK4 - MA HCl 1:1.5
NaOH - H2O 1:2
BK4 - DCM 1:3
 
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