quantity of Magnesium sulfate for drying acetone

mithyl2

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what is the best ratio to use when using anhydrous Magnesium sulfate to dry acetone?

for example how much anhydrous Magnesium sulfate should be used to dry 100ml of acetone?

thanks for any help
 

Osmosis Vanderwaal

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I do the math and double it. A molecule of MS can bind 7 molecules of water ( anhydrous to heptahydrate)
98% acetone ( just a number because we need one) 100ml
98 ml acetone, 2ml h2o
2ml H2O= 2 grams H2O H2O mol mass=18grams
2g H2O=0.11111111111111111 MOLES
MgSo⁴ mol.wt.120.37

MgSO⁴7h²O mol.wt 246.48
That's right, 1 mol. Of MgSo⁴ holds 1.36 mol of h².
0.11111111/1.36=.089611
.089611 MOLES of MgSo⁴ x 120.37
9.834 grams og MgSo⁴absorbs 2 ml of water
Let's Just call it 10 and say that
5 grams of H2So4 absorbs 1gram/ml of water
1gram is 1% of 100ml don't skimp
 

mithyl2

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you went above and beyond to inform me here. thank you.
i've been dumping far too much of this into my acetone. smh...

you put sulfuric acid at the end. is that a mistake?
 

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No I edited my post, I always think in terms of meth because there's no amphetamine here. This "formula " jumble of bullshit is basically how you balance all reactions. 1 molecule to 1 molecule stoichiometry. Even if it is 2:1, 3:1, generally an excess, you need to balance the number of molecules, which doesn't mean the weight
 
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