Simple methylone synthesis (bk-MDMA)

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The table shows the density of 40% methylamine as 0.89g/ cm3, hence 7.18g of pure methylamine gas is obtained in 20ml.
Let us compare the molecular weights of methylamine and its hydrochloride:
M (CH3NH2)HCl = 67.518 g/mol
M CH3NH2 = 31.057 g/mol.
Ratio = 2.174
If you use the proportions from the synthesis, you will need 15.6g of methylamine hydrochloride to replace 20ml of 40% methylamine solution.
Methylamine hydrochloride needs to be dissolved beforehand in the proportion of 1g to 2.5ml water (15.6g and 39ml).
Prepare sodium hydroxide (NaOH) solution of 18g and 54ml water, let it cool and pour it into a flask with 2-bromo-3,4-methylenedioxypropiophenone solution. After that, add methylamine hydrochloride solution. Then continue according to the instructions.
 
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arundo

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Hello, I'm doing the math, and I see that the molar ratio of NaOH isn't equivalent with methylamine HCl. It doubles. It's for some reason?
 

Osmosis Vanderwaal

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Someone asked me the other day about using sesamol to get MD-P1P, and it looked possible. Any opinion on that?
DBVaQ6hicT
 
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