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Yes, that will always works right, but you will never get the same yield on a regular basis because it is a gamble unless you have a decent amalgam. After all, I have the same problem. An optimal reaction would be to convert the aluminum completely into amalgam, i.e. add exactly the right amount of mercury salt and then after the reduction, have no solid aluminum/amalgam left in the flask, because thus everything has been converted with P2NP.
It simply makes more sense to wait the first time after adding mercury salt until it has reacted completely, i.e. no more bubbles are formed, and then to start the reduction of P2NP with new mercury salt and residual aluminum that is certainly still in the flask. If the reduction stops and there is still aluminum in the flask, a further addition of mercury salt would be necessary to convert these residues with P2NP.
I think this is the way we should go, after all I have learned here.
It simply makes more sense to wait the first time after adding mercury salt until it has reacted completely, i.e. no more bubbles are formed, and then to start the reduction of P2NP with new mercury salt and residual aluminum that is certainly still in the flask. If the reduction stops and there is still aluminum in the flask, a further addition of mercury salt would be necessary to convert these residues with P2NP.
I think this is the way we should go, after all I have learned here.