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I think something wrong with graph.
If you use L+-tartaric acid(cheaper and easier to find)the D enantiomer(amph,Meth) will be in the solution not in the solid as there appears.
If you use D-tartaric acid(more expensive and difficult to find) the D enantiomer(amph,Meth) will be in the solid.
Thanks.
If you use L+-tartaric acid(cheaper and easier to find)the D enantiomer(amph,Meth) will be in the solution not in the solid as there appears.
If you use D-tartaric acid(more expensive and difficult to find) the D enantiomer(amph,Meth) will be in the solid.
Thanks.
G.Patton
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His scheme is correct. Salt is precipitated into the solid state. No difference, d-amphetamine l-tartaric acid salt or l-amphetamine d-tartaric salt. You can change acid and get difference isomer in the solid state with following procedures.
P.S. same for methamphetamine.
P.S. same for methamphetamine.
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- By Ihml
I’m not Patton, but: it’d produce only D-meth of the ephedrine that was used was derived from a plant, since plants naturally only produce L-ephedrine (which turns into the opposite enantiomer after reaction - D-meth in this case). If chemically synthesized ephedrine was used, than you’d get racemic meth, because ephedrine synthesis isn’t stereospecific.