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depending on where you are in the world you can buy reagent test kits.
google 'reagent test kits'.
and do you mean, is snorting a good way to test the product?
google 'reagent test kits'.
and do you mean, is snorting a good way to test the product?
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Should the product be a/b extracted again after a/b extraction?
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how many minutes do you recommend to add because when I add the reaction solution turns white
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I don't understand, I do the whole synthesis as it says, but the synthesis doesn't disappear, I always fail, I go crazy, I'm going to kill myself.
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You can re-extract the basic acid of this salt that you obtained
Dissolve this salt in cold water, the ratio of water to salt is 1/1
Add 25% sodium hydroxide solution dropwise to pH12
You will notice an oily layer on top
Add the DCM solvent, mix it well, then throw it into the separating funnel and separate the DCM layers. The bottom extract it and keep it
Make a solution of 1 ml sulfuric acid and 10 ml acetone or isopropyl alcohol
Add a drop of sulfuric acid solution and a precipitate of amphetamine salts will form
Adjust pH6
Keep it in the freezer for two hours
Then take it out and put it on a filter to dry
Dissolve this salt in cold water, the ratio of water to salt is 1/1
Add 25% sodium hydroxide solution dropwise to pH12
You will notice an oily layer on top
Add the DCM solvent, mix it well, then throw it into the separating funnel and separate the DCM layers. The bottom extract it and keep it
Make a solution of 1 ml sulfuric acid and 10 ml acetone or isopropyl alcohol
Add a drop of sulfuric acid solution and a precipitate of amphetamine salts will form
Adjust pH6
Keep it in the freezer for two hours
Then take it out and put it on a filter to dry
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But if there's no amphetamine present in the salt, there won't be any oily layer (i think this is the amphetamine free base) forming on top, right? Tuco's problem seems to be the same as mine, where we are not synthesizing amphetamine, but another unidentified compound. I have repeatedly experienced this failure with the borohydride method as well, even when I used different forms of it
Yes, correct
If a transparent or slightly yellowish oil layer does not form in the separating funnel, it is important to see an oil layer when extracting the base.
If you don't see this, you won't have a free amphetamine base (maybe you reacted wrongly).
There is a concern about the tin chloride process and the extraction of the oxime in ethyl acetate. When extracting the oxime in ethyl acetate does delamination occur? Can you extract the oxime in a non-polar solvent, ether or DCM?
There is an interference of inorganic salts in this synthesis
If a transparent or slightly yellowish oil layer does not form in the separating funnel, it is important to see an oil layer when extracting the base.
If you don't see this, you won't have a free amphetamine base (maybe you reacted wrongly).
There is a concern about the tin chloride process and the extraction of the oxime in ethyl acetate. When extracting the oxime in ethyl acetate does delamination occur? Can you extract the oxime in a non-polar solvent, ether or DCM?
There is an interference of inorganic salts in this synthesis
Borohydride is a good reducing agent
Make sure it is pure copper chloride
I suggest you react p2np with aluminum amalgam. Try it in small quantities, starting with the correct amalgam. Add p2np in two stages and control the temperature of the amalgam.
Extract the free base with isopropyl alcohol
Make sure it is pure copper chloride
I suggest you react p2np with aluminum amalgam. Try it in small quantities, starting with the correct amalgam. Add p2np in two stages and control the temperature of the amalgam.
Extract the free base with isopropyl alcohol
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Can you write in detail how many ml dcm 2gr p2np calculation instead of ethyl acetate?