Marvin "Popcorn" Sutton
Expert
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C10H11BrO + CH5N → C11H15NO + HBr
As can be seen from the equation, one molecule of 2-bromo-4-methylpropiophenone produces one molecule of mephedrone.
C10H11BrO : 227.0977 g/mol
C11H15NO : 177.2429 g/mol
227.0977/177.2429=1.28127953
The coefficient is 1.28127953
This means that from 100g of 2-bromo-4-propiophenone, you will get 78.0469818g of mephedrone base.
The mass of mephedrone hydrochloride will increase by 1.19 g/cm3 and the coefficient will be 1.27273446
C11H15NO+HCl=177.2429+1.19=178.4329
227.0977/178.4329=1.27273446
100g(C10H11BrO)/1.27273446=78.5709849g(C11H15NO)
The theoretical yield of the reaction of 2-bromo-4-methylpropiophenone was 78.5709849g mephedrone hydrochloride. But it should be considered that it is difficult to achieve the theoretical yield, usually the loss is 20%.
As can be seen from the equation, one molecule of 2-bromo-4-methylpropiophenone produces one molecule of mephedrone.
C10H11BrO : 227.0977 g/mol
C11H15NO : 177.2429 g/mol
227.0977/177.2429=1.28127953
The coefficient is 1.28127953
This means that from 100g of 2-bromo-4-propiophenone, you will get 78.0469818g of mephedrone base.
The mass of mephedrone hydrochloride will increase by 1.19 g/cm3 and the coefficient will be 1.27273446
C11H15NO+HCl=177.2429+1.19=178.4329
227.0977/178.4329=1.27273446
100g(C10H11BrO)/1.27273446=78.5709849g(C11H15NO)
The theoretical yield of the reaction of 2-bromo-4-methylpropiophenone was 78.5709849g mephedrone hydrochloride. But it should be considered that it is difficult to achieve the theoretical yield, usually the loss is 20%.
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