Metamfetamino sintezė iš P2P redukuojant NaBH4. Vidutinės apimties.

btcboss2022

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Sveiki,

Po daugybės bandymų, atliktų naudojant metilamino HCL pagal šį metodą, pasidalysiu geriausiu būdu, kurį radau, kaip gauti metamfetamino laisvąją bazę dideliu mastu:

  • 966 gr P2P
  • 14 litrų metanolio
  • 1183 gr Metilamino HCL
  • 638 gr NaOH
  • 452 gr Bevandenis natrio sulfatas
  • 105 gr NaBH4
  • 35 l distiliuoto vandens
  • 7 litrai DCM

- Pripildykite reaktorių 14 l metanolio
- Maišant ištirpinkite metilamino HCL
- Nustatykite reaktoriaus temperatūrą 0C (ne mišinio temperatūrą) ir įpilkite NaOH, temperatūra padidės
- Kai temperatūra vėl pasieks 20C, įpilkite P2P, temperatūra padidės, maišykite 45 min. iki 1 val.
- Įpilkite 252 g bevandenio natrio sulfato
- Kai mišinio temperatūra pasiekia 8C, pradėkite dalimis pilti NaBH4, neviršydami 20C temperatūros
- Kai bus įdėtas visas NaBH4, leiskite mišiniui maišytis 20C temperatūroje maždaug 2 valandas, kol nustos burbuliuoti
- Įpilkite vandens ir maišykite 5 min.
- Įpilkite DCM ir maišykite 10 min.
- Nustokite maišyti ir leiskite sluoksniams atsiskirti
- Pasilikite apatinį sluoksnį, o viršutinį išmeskite (nėra naudinga ekstrahuoti šią vandeninę fazę)
- Į išsaugotą sluoksnį įpilkite 200 g bevandenio natrio sulfato ir išmaišykite
- Filtruokite Buchnerio piltuvu
- Išgarinkite DCM
- Gaunama švari ir kvapni metamfetamino laisvoji bazė

;-)
 
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snowbones

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Is the 35 litres of water added to ensure seperation of the dcm and water cos of the methanol present to stop it all mixing?
and are you using a 100 litre HDPE paint bucket as the reaction vessel?
 

Chemistry lntern

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Excuse me! Is it necessary to use an ice bath when setting the reaction temperature to 0 degrees (not the temperature of the mixture
 

Atompower

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Has any one trying this method of btc boss and had success with his write up
 

rage565

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Is there a video of this procedure available?
 

G.Patton

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Have you tried to open Video section?
 

Grubby

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Is 15g of NaBH4 enough as the reducing agent for 138g of P2P? Or should I add a small amount of reducing agent to avoid some side reactions?
 

G.Patton

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Hello, yes it's not enough. You have to add at least equimolar amount 38.91g of NaBH4. It's even worth to add a little more, ~1.1 eqviv 42.8g.
 

Grubby

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Idol, there must be a special reason why you choose to use less reducing agent! For example, to avoid certain side reactions or to favor certain steps? Please Master, please enlighten me on the mystery behind this.
 

Chemistry lntern

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How does methylamine hydrochloride and methanol produce a 10% methylamine methanol solution
 
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