Abi tulkojumi darbojas, un abi ir labi.
4-MMC (mefedrona) sintēze. Pilnīga video pamācība.
C10H11BrO + CH5N → C11H15NO + HBr
Kā redzams no vienādojuma, no vienas 2-brom-4-metilpropiofenona molekulas rodas viena mefedrona molekula.
C10H11BrO : 227,0977 g/mol
C11H15NO : 177,2429 g/mol
227.0977/177.2429=1.28127953
Koeficients ir 1,28127953
Tas nozīmē, ka no 100 g 2-brom-4-propiofenona iegūsiet 78,0469818 g mefedrona bāzes.
Mefedrona hidrohlorīda masa palielināsies par 1,19 g/cm3 , un koeficients būs 1,27273446.
C11H15NO+HCl=177.2429+1.19=178.4329
227.0977/178.4329=1.27273446
100g(C10H11BrO)/1.27273446=78.5709849g(C11H15NO)
Teorētiskais iznākums 2-brom-4-metilpropiofenona reakcijā bija 78,5709849 g mefedrona hidrohlorīda. Tomēr jāņem vērā, ka teorētisko iznākumu ir grūti sasniegt, parasti zaudējumi ir 20 %.
Kā redzams no vienādojuma, no vienas 2-brom-4-metilpropiofenona molekulas rodas viena mefedrona molekula.
C10H11BrO : 227,0977 g/mol
C11H15NO : 177,2429 g/mol
227.0977/177.2429=1.28127953
Koeficients ir 1,28127953
Tas nozīmē, ka no 100 g 2-brom-4-propiofenona iegūsiet 78,0469818 g mefedrona bāzes.
Mefedrona hidrohlorīda masa palielināsies par 1,19 g/cm3 , un koeficients būs 1,27273446.
C11H15NO+HCl=177.2429+1.19=178.4329
227.0977/178.4329=1.27273446
100g(C10H11BrO)/1.27273446=78.5709849g(C11H15NO)
Teorētiskais iznākums 2-brom-4-metilpropiofenona reakcijā bija 78,5709849 g mefedrona hidrohlorīda. Tomēr jāņem vērā, ka teorētisko iznākumu ir grūti sasniegt, parasti zaudējumi ir 20 %.
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- By whitelabel
Greetings
4mp to 4mmc successfully this way for me but starting 4mp was yellow so bromination done as per process.
Resultant mephedrone was a pasty powder and not crystal like salt as in video. Power was also low even after crystallization. Any thoughts on the pasty powder and low power. Yield was about 120 gms recrystallized from 400 ml 4mp.
Is there any way to purify the 4mp we get to start with or is that fine?
Would a superior product be possible if 4mp is brominated using NBs and PTSA, purified with a solvent nd then make the nmp synthesis from that 2b4m?
Thanks in advance. Tc
4mp to 4mmc successfully this way for me but starting 4mp was yellow so bromination done as per process.
Resultant mephedrone was a pasty powder and not crystal like salt as in video. Power was also low even after crystallization. Any thoughts on the pasty powder and low power. Yield was about 120 gms recrystallized from 400 ml 4mp.
Is there any way to purify the 4mp we get to start with or is that fine?
Would a superior product be possible if 4mp is brominated using NBs and PTSA, purified with a solvent nd then make the nmp synthesis from that 2b4m?
Thanks in advance. Tc
Es nepievienoju acetonu, tikai MMC frībāzi benzolā, un es iepilināju 30 % HCl ar pH 5,5. Skābi pievienoju lēnām. Vai problēma varētu būt acetons? Es aizmirsu, jo parasti es skābinu ar DCM+ūdeni, tāpēc acetons man neienāca prātā. Kā jūs paskābinājāt attēlā redzamo skaistumu? Liels paldies.
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- By William D.
Ja jūs izmantojat sālsskābi, jums ir nepieciešams šķīdinātājs, kas saista ūdeni. Tas ir acetons vai spirts (etanols, propanols).
Sveiki, draugi, kur es varu atrast NMP?
This method can use 1451-82-7?
Of course you can, in which case you skip the first bromination step and proceed to the methylamination step.
@Marvin "Popcorn" Sutton can we scale this up using a 50litre batch reactor and drop the bromine Benzene mix from the reactors dropping funnel without any issues?
Bromine mix in an enclosed dropping funnel is a litle scary
Bromine mix in an enclosed dropping funnel is a litle scary